Here is how the "$150 Roulette Strategy" is carried out:

1.      Bet $50 on first twelve (1^st 12). Odds of winning 1:3.

2.      Bet $50 on second twelve (2^nd 12). Odds of winning 1:3.

3.      Bet $5 on 10 random numbers from the third twelve (3^rd 12). Odds of winning 1:35.

After you place such a bet you will see that you have covered all numbers on the roulette table except for three – 0 and two numbers from 3^rd 12. If a number from 1^st 12 comes out, you win $150 or exactly what you have bet – you are even. If a number from 2^nd 12 comes out, the situation is the same – you will be even. If one of the numbers from 3^rd 12 that you have bet on comes out, you will win $180 and therefore you will have generated $30 profit.

Example:

I bet $50 on 1^st 12, $50 on 2^nd 12 and $5 on the following numbers: 25, 26, 27, 28, 29, 30, 31, 32, 33 and 34. This makes a total bet of $150 and as you can see we can lose only if 0, 35, 36 numbers come out. The chance for just these numbers to come out is very small but, anyway, if you are very unlucky that day it may happen to you.

After all, the main idea is to have one of the numbers from 3^rd 12 to come out (25, 26, 27, 28, 29, 30, 31, 32, 33 or 34) because that’s when we will have profit of $30. If a number from 1 to 24 comes out, we won’t lose anything because our bet on the dozens will recover the loses.

The "$150 Roulette Strategy" may be carried out with different amounts of the stake per spin, depending on the amount that is at your disposal: $300 stake ($60 profit per spin), $600 stake ($120 profit per spin) or $900 stake ($180 profit per spin).

You may choose the 10 numbers to be from 1^st 12, if you prefer, but you need to keep the configuration of the roulette strategy. This means that if you choose to bet on 10 numbers from 1^st 12, you will need to place your other bets on 2^nd 12 and 3^rd 12 instead of 1^st 12 and 2^nd 12. You can do the same if you want to bet on 10 numbers from 2^nd 12 (your other bets will be on 1^st 12  and 3^rd 12).

Play Now